Work Done calculator
Work Done
Energy transferred when a force moves an object. Only the force component along the direction of motion does work.
When does a force do work? If you push a box and it slides, the part of your force that points along the displacement does work. If you push straight down on a stationary box, no work is done.
🌿 Natural example: A glacier sliding downhill does work on the bedrock, eroding the valley floor.
🏠 Daily life: Lifting a suitcase straight up from the floor to a table does work equal to its weight times the height. Force and displacement are both upward, so θ = 0 and cos θ = 1.
Work is zero when the force is perpendicular to displacement (θ = 90°). All inputs converted to SI (N, m, rad) internally.
Solved Examples
These examples demonstrate how the calculator converts your inputs into standard SI units—Newtons (N), meters (m), and degrees/radians—before computing mechanical work using the core physics formula:
W = F × d × cos(θ)
1. The Horizontal Push (Zero Degree Angle)
A warehouse worker pushes a heavy crate across a level floor with a horizontal force of 80 N over a distance of 5 m. Because the push is in the exact same direction as the movement, the angle θ is 0°.
- Input: Force = 80 N, Displacement = 5 m, Angle = 0°
- Step 1 (Unit & Angle Check): Values are in SI units. Since θ = 0°, cos(0°) = 1.
- Step 2 (Calculate): W = 80 × 5 × 1 W = 400 J
- Calculator Output: 400.00 J (400 Joules of energy transferred)
2. The Angled Pull (Standard Metric)
A child pulls a wooden wagon along the sidewalk by a rope. The child pulls with a force of 60 N at an upward angle of 30° above the horizontal, moving the wagon 12 m.
- Input: Force = 60 N, Displacement = 12 m, Angle = 30°
- Step 1 (Angle Check): cos(30°) ≈ 0.8660
- Step 2 (Calculate): W = 60 × 12 × 0.8660 W = 623.54 J
- Calculator Output: 623.54 J (Notice: Pulling at an angle wastes some upward force, so less horizontal work is done than if θ were 0°!)
3. The Construction Crane (Imperial to SI Conversions)
A winch pulls a heavy steel beam with a tension force of 500 lbf over a distance of 40 ft along a track, at an angle of 15°.
- Input: Force = 500 lbf, Displacement = 40 ft, Angle = 15°
- Step 1 (Convert Force): Multiply lbf by 4.44822 → 2,224.11 N
- Step 2 (Convert Distance): Multiply ft by 0.3048 → 12.192 m
- Step 3 (Calculate): W = 2,224.11 × 12.192 × cos(15°) W = 27,116.35 × 0.9659 = 26,192.56 J (or ≈ 26.19 kJ)
- Calculator Output: 26,192.56 J
Practice Problems (Unsolved)
Test your understanding of mechanical work by plugging these real-world scenarios into the calculator or solving them by hand!
- The Lawnmower Push: A homeowner pushes a manual lawnmower with a force of 120 N directed downward along the handle at an angle of 45° to the ground. If they push it for 25 m, how much work is done?
- The Perpendicular Carry: A waiter carries a tray weighing 15 N straight across a restaurant room for 10 m. The lifting force is pointing straight up (90° to the horizontal walking direction). How much work does the lifting force do on the tray?
- The Tractor Tow: A farm tractor pulls a broken trailer using a cable with 1,200 lbf of tension at a slight 10° angle over a distance of 150 feet. What is the work done in Joules?
- The Sled Dog: A sled dog pulls a sled across the snow with a force of 200 N over a displacement of 0.5 km (500 m) at an angle of 20°. How many kilojoules (kJ) of work are expended?
Answer Key
- Problem 1: 2,121.32 J (120 × 25 × cos(45°))
- Problem 2: 0 J (Because θ = 90° and cos(90°) = 0, no physical work is done in the direction of motion!)
- Problem 3: 240,111.96 J or ≈ 240.11 kJ (Force → 5,337.86 N; Disp → 45.72 m; cos(10°) → 0.9848)
- Problem 4: 93,969.26 J or ≈ 93.97 kJ (200 × 500 × 0.9397)
Common Mistakes & Pitfalls
When calculating mechanical work by hand or using online physics tools, avoid these frequent traps:
1. Forgetting the Angle (Assuming cos θ = 1)
If a force is applied at an angle (like pulling a rolling suitcase by an inclined handle), you cannot simply multiply Force × Distance. Only the horizontal component of the force actually pulls the suitcase forward. Forgetting to multiply by cos(θ) will artificially inflate your calculated energy!
2. The 90-Degree Trap (Work Can Be Zero!)
In physics, “work” has a very strict definition: a force must cause displacement in the direction of that force. If you hold a heavy 50 kg box in your arms and walk horizontally across a room, your arms exert an upward force, but the movement is horizontal (θ = 90°). Because cos(90°) = 0, the mathematical work done by your lifting force is zero Joules, even though your muscles feel tired!
3. Mixing Up Radians and Degrees
In trigonometry, calculators and programming languages (like JavaScript or Excel) process angles in radians by default, not degrees! If you plug 30° directly into a standard code formula without converting it (30 × π / 180), the computer will think you mean 30 radians (about 1,718 degrees), leading to completely wrong or negative numbers. Why your calculator helps: Our tool automatically detects whether you selected degrees or radians and handles the background math safely.
4. Confusing Work with Power
Work (measured in Joules) is the total amount of energy transferred to move an object. Power (measured in Watts) is how fast that work is done over time (Power = Work / Time). Lifting a 100 kg barbell takes the exact same amount of Work whether you lift it in 2 seconds or 20 seconds—but doing it in 2 seconds requires much more Power!oward infinity. Always ensure your radius is greater than zero ($r > 0$).bined forces acting on the object.
Frequently Asked Questions
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